# 9.E: Two-Sample Problems (Exercises)

These are homework exercises to accompany the Textmap created for "Introductory Statistics" by Shafer and Zhang. Complementary General Chemistry question banks can be found for other Textmaps and can be accessed here. In addition to these publicly available questions, access to private problems bank for use in exams and homework is available to faculty only on an individual basis; please contact Delmar Larsen for an account with access permission.

## 9.1: Comparison of Two Population Means: Large, Independent Samples

### Q9.1.1

1. Construct the confidence interval for μ1μ2 for the level of confidence and the data from independent samples given.

1. 90% confidence,

n1=45x1=27s1=2

n2=60x2=22s2=3

2. 99% confidence,

n1=30x1=112s1=9

n2=40x2=98s2=4

2. Construct the confidence interval for μ1μ2 for the level of confidence and the data from independent samples given.

1. 95% confidence,

n1=110x1=77s1=15

n2=85x2=79s2=21

2. 90% confidence,

n1=65x1=83s1=12

n2=65x2=74s2=8

3. Construct the confidence interval for μ1μ2 for the level of confidence and the data from independent samples given.

1. 99.5% confidence,

n1=130x1=27.2s1=2.5

n2=155x2=38.8s2=4.6

2. 95% confidence,

n1=68x1=215.5s1=12.3

n2=84x2=287.8s2=14.1

4. Construct the confidence interval for μ1μ2 for the level of confidence and the data from independent samples given.

1. 99.9% confidence,

n1=275x1=70.2s1=1.5

n2=325x2=63.4s2=1.1

2. 90% confidence,

n1=120x1=35.5s1=0.75

n2=146x2=29.6s2=0.80

5. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach. Compute the p-value of the test as well.

1. Test H0:μ1μ2=3 vs. Ha:μ1μ23 @ α=0.05,

n1=35x1=25s1=1

n2=45x2=19s2=2

2. Test H0:μ1μ2=25 vs. Ha:μ1μ2<25 @ α=0.10,

n1=85x1=188s1=15

n2=62x2=215s2=19

6. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach. Compute the p-value of the test as well.

1. Test H0:μ1μ2=45 vs. Ha:μ1μ2>45 @ α=0.001,

n1=200x1=1312s1=35

n2=225x2=1256s2=28

2. Test H0:μ1μ2=12 vs. Ha:μ1μ212 @ α=0.10,

n1=35x1=121s1=6

n2=40x2=135s2=7

7. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach. Compute the p-value of the test as well.

1. Test H0:μ1μ2=0 vs. Ha:μ1μ20 @ α=0.01,

n1=125x1=46s1=10

n2=90x2=50s2=13

2. Test H0:μ1μ2=20 vs. Ha:μ1μ2>20 @ α=0.05,

n1=40x1=142s1=11

n2=40x2=118s2=10

8. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach. Compute the p-value of the test as well.

1. Test H0:μ1μ2=13 vs. Ha:μ1μ2<13 @ α=0.01,

n1=35x1=100s1=2

n2=35x2=88s2=2

2. Test H0:μ1μ2=10 vs. Ha:μ1μ210 @ α=0.10,

n1=146x1=62s1=4

n2=120x2=73s2=7

9. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach.

1. Test H0:μ1μ2=57 vs. Ha:μ1μ2<57 @ α=0.10,

n1=117x1=1309s1=42

n2=133x2=1258s2=37

2. Test H0:μ1μ2=1.5 vs. Ha:μ1μ21.5 @ α=0.20,

n1=65x1=16.9s1=1.3

n2=57x2=18.6s2=1.1

10. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach.

1. Test H0:μ1μ2=10.5 vs. Ha:μ1μ2>10.5 @ α=0.01,

n1=64x1=85.6s1=2.4

n2=50x2=95.3s2=3.1

2. Test H0:μ1μ2=110 vs. Ha:μ1μ2110 @ α=0.02,

n1=176x1=1918s1=68

n2=241x2=1782s2=146

11. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach.

1. Test H0:μ1μ2=50 vs. Ha:μ1μ2>50 @ α=0.005,

n1=72x1=272s1=26

n2=103x2=213s2=14

2. Test H0:μ1μ2=7.5 vs. Ha:μ1μ27.5 @ α=0.10,

n1=52x1=94.3s1=2.6

n2=38x2=88.6s2=8.0

12. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach.

1. Test H0:μ1μ2=23 vs. Ha:μ1μ2<23 @ α=0.20,

n1=314x1=198s1=12.2

n2=220x2=176s2=11.5

2. Test H0:μ1μ2=4.4 vs. Ha:μ1μ24.4 @ α=0.05,

n1=32x1=40.3s1=0.5

n2=30x2=35.5s2=0.7

### Applications

1. In order to investigate the relationship between mean job tenure in years among workers who have a bachelor’s degree or higher and those who do not, random samples of each type of worker were taken, with the following results.

n x s
Bachelor’s degree or higher 155 5.2 1.3
No degree 210 5.0 1.5
1. Construct the 99% confidence interval for the difference in the population means based on these data.
2. Test, at the 1% level of significance, the claim that mean job tenure among those with higher education is greater than among those without, against the default that there is no difference in the means.
3. Compute the observed significance of the test.
2. Records of 40 used passenger cars and 40 used pickup trucks (none used commercially) were randomly selected to investigate whether there was any difference in the mean time in years that they were kept by the original owner before being sold. For cars the mean was 5.3 years with standard deviation 2.2 years. For pickup trucks the mean was 7.1 years with standard deviation 3.0 years.

1. Construct the 95% confidence interval for the difference in the means based on these data.
2. Test the hypothesis that there is a difference in the means against the null hypothesis that there is no difference. Use the 1% level of significance.
3. Compute the observed significance of the test in part (b).
3. In previous years the average number of patients per hour at a hospital emergency room on weekends exceeded the average on weekdays by 6.3 visits per hour. A hospital administrator believes that the current weekend mean exceeds the weekday mean by fewer than 6.3 hours.

1. Construct the 99% confidence interval for the difference in the population means based on the following data, derived from a study in which 30 weekend and 30 weekday one-hour periods were randomly selected and the number of new patients in each recorded.

n x s
Weekends 30 13.8 3.1
Weekdays 30 8.6 2.7
2. Test at the 5% level of significance whether the current weekend mean exceeds the weekday mean by fewer than 6.3 patients per hour.
3. Compute the observed significance of the test.
4. A sociologist surveys 50 randomly selected citizens in each of two countries to compare the mean number of hours of volunteer work done by adults in each. Among the 50 inhabitants of Lilliput, the mean hours of volunteer work per year was 52, with standard deviation 11.8. Among the 50 inhabitants of Blefuscu, the mean number of hours of volunteer work per year was 37, with standard deviation 7.2.

1. Construct the 99% confidence interval for the difference in mean number of hours volunteered by all residents of Lilliput and the mean number of hours volunteered by all residents of Blefuscu.
2. Test, at the 1% level of significance, the claim that the mean number of hours volunteered by all residents of Lilliput is more than ten hours greater than the mean number of hours volunteered by all residents of Blefuscu.
3. Compute the observed significance of the test in part (b).
5. A university administrator asserted that upperclassmen spend more time studying than underclassmen.

1. Test this claim against the default that the average number of hours of study per week by the two groups is the same, using the following information based on random samples from each group of students. Test at the 1% level of significance.

n x s
Upperclassmen 35 15.6 2.9
Underclassmen 35 12.3 4.1
2. Compute the observed significance of the test.
6. An kinesiologist claims that the resting heart rate of men aged 18 to 25 who exercise regularly is more than five beats per minute less than that of men who do not exercise regularly. Men in each category were selected at random and their resting heart rates were measured, with the results shown.

n x s
Regular exercise 40 63 1.0
No regular exercise 30 71 1.2
1. Perform the relevant test of hypotheses at the 1% level of significance.
2. Compute the observed significance of the test.
7. Children in two elementary school classrooms were given two versions of the same test, but with the order of questions arranged from easier to more difficult in Version A and in reverse order in Version B. Randomly selected students from each class were given Version Aand the rest Version B. The results are shown in the table.

n x s
Version A 31 83 4.6
Version B 32 78 4.3
1. Construct the 90% confidence interval for the difference in the means of the populations of all children taking Version A of such a test and of all children taking Version B of such a test.
2. Test at the 1% level of significance the hypothesis that the A version of the test is easier than the B version (even though the questions are the same).
3. Compute the observed significance of the test.
8. The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the city center that departs at 8:15 a.m. or the one that departs at 8:30 a.m. The following sample statistics are assembled by the Transit Authority.

n x s
8:15 a.m. train 30 323 41
8:30 a.m. train 45 356 45
1. Construct the 90% confidence interval for the difference in the mean number of daily travellers on the 8:15 train and the mean number of daily travellers on the 8:30 train.
2. Test at the 5% level of significance whether the data provide sufficient evidence to conclude that more passengers ride the 8:30 train.
3. Compute the observed significance of the test.
9. In comparing the academic performance of college students who are affiliated with fraternities and those male students who are unaffiliated, a random sample of students was drawn from each of the two populations on a university campus. Summary statistics on the student GPAs are given below.

n x s
Fraternity 645 2.90 0.47
Unaffiliated 450 2.88 0.42

Test, at the 5% level of significance, whether the data provide sufficient evidence to conclude that there is a difference in average GPA between the population of fraternity students and the population of unaffiliated male students on this university campus.

10. In comparing the academic performance of college students who are affiliated with sororities and those female students who are unaffiliated, a random sample of students was drawn from each of the two populations on a university campus. Summary statistics on the student GPAs are given below.

n x s
Sorority 330 3.18 0.37
Unaffiliated 550 3.12 0.41

Test, at the 5% level of significance, whether the data provide sufficient evidence to conclude that there is a difference in average GPA between the population of sorority students and the population of unaffiliated female students on this university campus.

11. The owner of a professional football team believes that the league has become more offense oriented since five years ago. To check his belief, 32 randomly selected games from one year’s schedule were compared to 32 randomly selected games from the schedule five years later. Since more offense produces more points per game, the owner analyzed the following information on points per game (ppg).

n x s
ppg previously 32 20.62 4.17
ppg recently 32 22.05 4.01

Test, at the 10% level of significance, whether the data on points per game provide sufficient evidence to conclude that the game has become more offense oriented.

12. The owner of a professional football team believes that the league has become more offense oriented since five years ago. To check his belief, 32 randomly selected games from one year’s schedule were compared to 32 randomly selected games from the schedule five years later. Since more offense produces more offensive yards per game, the owner analyzed the following information on offensive yards per game (oypg).

n x s
oypg previously 32 316 40
oypg recently 32 336 35

Test, at the 10% level of significance, whether the data on offensive yards per game provide sufficient evidence to conclude that the game has become more offense oriented.

### Large Data Set Exercises

1. Large Data Sets 1A and 1B list the SAT scores for 1,000 randomly selected students. Denote the population of all male students as Population 1 and the population of all female students as Population 2.

http://www.gone.2012books.lardbucket.org/sites/all/files/data1A.xls

http://www.gone.2012books.lardbucket.org/sites/all/files/data1B.xls

1. Restricting attention to just the males, find n1x1, and s1. Restricting attention to just the females, find n2x2, and s2.
2. Let μ1 denote the mean SAT score for all males and μ2 the mean SAT score for all females. Use the results of part (a) to construct a 90% confidence interval for the difference μ1μ2.
3. Test, at the 5% level of significance, the hypothesis that the mean SAT scores among males exceeds that of females.
2. Large Data Sets 1A and 1B list the GPAs for 1,000 randomly selected students. Denote the population of all male students as Population 1 and the population of all female students as Population 2.

http://www.gone.2012books.lardbucket.org/sites/all/files/data1A.xls

http://www.gone.2012books.lardbucket.org/sites/all/files/data1B.xls

1. Restricting attention to just the males, find n1x1, and s1. Restricting attention to just the females, find n2x2, and s2.
2. Let μ1 denote the mean GPA for all males and μ2 the mean GPA for all females. Use the results of part (a) to construct a 95% confidence interval for the difference μ1μ2.
3. Test, at the 10% level of significance, the hypothesis that the mean GPAs among males and females differ.
3. Large Data Sets 7A and 7B list the survival times for 65 male and 75 female laboratory mice with thymic leukemia. Denote the population of all such male mice as Population 1 and the population of all such female mice as Population 2.

http://www.gone.2012books.lardbucket.org/sites/all/files/data7A.xls

http://www.gone.2012books.lardbucket.org/sites/all/files/data7B.xls

1. Restricting attention to just the males, find n1x1, and s1. Restricting attention to just the females, find n2x2, and s2.
2. Let μ1 denote the mean survival for all males and μ2 the mean survival time for all females. Use the results of part (a) to construct a 99% confidence interval for the difference μ1μ2.
3. Test, at the 1% level of significance, the hypothesis that the mean survival time for males exceeds that for females by more than 182 days (half a year).
4. Compute the observed significance of the test in part (c).

1. (4.20,5.80),
2. (18.54,9.46)
1.
1. (12.81,10.39),
2. (76.50,68.10)
2.
1. Z = 8.753, ±z0.025=±1.960, reject H0p-value = 0.0000;
2. Z=0.687z0.10=1.282, do not reject H0p-value = 0.2451
3.
1. Z = 2.444, ±z0.005=±2.576, do not reject H0p-value = 0.0146.
2. Z = 1.702, z0.05=1.645, reject H0p-value = 0.0446
4.
1. Z=1.19p-value = 0.1170, do not reject H0;
2. Z=0.92p-value = 0.3576, do not reject H0
5.
1. Z = 2.68, p-value = 0.0037, reject H0;
2. Z=1.34p-value = 0.1802, do not reject H0
6.
1. 0.2±0.4,
2. Z = 1.360, z0.01=2.326, do not reject H0 (not greater)
3. p-value = 0.0869
1.
1. 5.2±1.9,
2. Z=1.466z0.050=1.645, do not reject H0 (exceeds by 6.3 or more)
3. p-value = 0.0708
2.
1. Z = 3.888, z0.01=2.326, reject H0 (upperclassmen study more)
2. p-value = 0.0001
3.
1. 5±1.8,
2. Z = 4.454, z0.01=2.326, reject H0 (Test A is easier)
3. p-value = 0.0000
4.
5. Z = 0.738, ±z0.025=±1.960, do not reject H0 (no difference)

6.
7. Z=1.398z0.10=1.282, reject H0 (more offense oriented)

8.
1. n1=419x1=1540.33s1=205.40n2=581x2=1520.38, and s2=217.34.
2. (2.24,42.15)
3. H0:μ1μ2=0 vs. Ha:μ1μ2>0. Test Statistic: Z = 1.48. Rejection Region: [1.645,). Decision: Fail to reject H0.
1.
1. n1=65x1=665.97s1=41.60n2=75x2=455.89, and s2=63.22.
2. (187.06,233.09)
3. H0:μ1μ2=182 vs. Ha:μ1μ2>182. Test Statistic: Z = 3.14. Rejection Region: [2.33,). Decision: Reject H0.
4. pvalue=0.0008

## 9.2: Comparison of Two Population Means: Small, Independent Samples

### Basic

In all exercises for this section assume that the populations are normal and have equal standard deviations.

1. Construct the confidence interval for  μ1μ2 for the level of confidence and the data from independent samples given.

1. 95% confidence,

n1=10 x1=120 s1=2

n2=15 x2=101 s2=4

2. 99% confidence,

n1=6 x1=25 s1=1

n2=12 x2=17 s2=3

2. Construct the confidence interval for  μ1μ2 for the level of confidence and the data from independent samples given.

1. 90% confidence,

n1=28 x1=212 s1=6

n2=23 x2=198 s2=5

2. 99% confidence,

n1=14 x1=68 s1=8

n2=20 x2=43 s2=3

3. Construct the confidence interval for  μ1μ2 for the level of confidence and the data from independent samples given.

1. 99.9% confidence,

n1=35 x1=6.5 s1=0.2

n2=20 x2=6.2 s2=0.1

2. 99% confidence,

n1=18 x1=77.3 s1=1.2

n2=32 x2=75.0 s2=1.6

4. Construct the confidence interval for  μ1μ2 for the level of confidence and the data from independent samples given.

1. 99.5% confidence,

n1=40 x1=85.6 s1=2.8

n2=20 x2=73.1 s2=2.1

2. 99.9% confidence,

n1=25 x1=215 s1=7

n2=35 x2=185 s2=12

5. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach.

1. Test  H0:μ1μ2=11 vs.  Ha:μ1μ2>11 @  α=0.025,

n1=6 x1=32 s1=2

n2=11 x2=19 s2=1

2. Test  H0:μ1μ2=26 vs.  Ha:μ1μ226 @  α=0.05,

n1=17 x1=166 s1=4

n2=24 x2=138 s2=3

6. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach.

1. Test  H0:μ1μ2=40 vs.  Ha:μ1μ2<40 @  α=0.10,

n1=14 x1=289 s1=11

n2=12 x2=254 s2=9

2. Test  H0:μ1μ2=21 vs.  Ha:μ1μ221 @  α=0.05,

n1=23 x1=130 s1=6

n2=27 x2=113 s2=8

7. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach.

1. Test  H0:μ1μ2=15 vs.  Ha:μ1μ2<15 @  α=0.10,

n1=30 x1=42 s1=7

n2=12 x2=60 s2=5

2. Test  H0:μ1μ2=103 vs.  Ha:μ1μ2103 @  α=0.10,

n1=17 x1=711 s1=28

n2=32 x2=598 s2=21

8. Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach.

1. Test  H0:μ1μ2=75 vs.  Ha:μ1μ2>75 @  α=0.025,

n1=45 x1=674 s1=18

n2=29 x2=591 s2=13

2. Test  H0:μ1μ2=20 vs.  Ha:μ1μ220 @  α=0.005,

n1=30 x1=137 s1=8

n2=19 x2=166 s2=11

9. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach. (The p-value can be only approximated.)

1. Test  H0:μ1μ2=12 vs.  Ha:μ1μ2>12 @  α=0.01,

n1=20 x1=133 s1=7

n2=10 x2=115 s2=5

2. Test  H0:μ1μ2=46 vs.  Ha:μ1μ246 @  α=0.10,

n1=24 x1=586 s1=11

n2=27 x2=535 s2=13

10. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach. (The p-value can be only approximated.)

1. Test  H0:μ1μ2=38 vs.  Ha:μ1μ2<38 @  α=0.01,

n1=12 x1=464 s1=5

n2=10 x2=432 s2=6

2. Test  H0:μ1μ2=4 vs.  Ha:μ1μ24 @  α=0.005,

n1=14 x1=68 s1=2

n2=17 x2=67 s2=3

11. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach. (The p-value can be only approximated.)

1. Test  H0:μ1μ2=50 vs.  Ha:μ1μ2>50 @  α=0.01,

n1=30 x1=681 s1=8

n2=27 x2=625 s2=8

2. Test  H0:μ1μ2=35 vs.  Ha:μ1μ235 @  α=0.10,

n1=36 x1=325 s1=11

n2=29 x2=286 s2=7

12. Perform the test of hypotheses indicated, using the data from independent samples given. Use the p-value approach. (The p-value can be only approximated.)

1. Test  H0:μ1μ2=4 vs.  Ha:μ1μ2<4 @  α=0.05,

n1=40 x1=80 s1=5

n2=25 x2=87 s2=5

2. Test  H0:μ1μ2=21 vs.  Ha:μ1μ221 @  α=0.01,

n1=15 x1=192 s1=12

n2=34 x2=180 s2=8

### Applications

1. A county environmental agency suspects that the fish in a particular polluted lake have elevated mercury level. To confirm that suspicion, five striped bass in that lake were caught and their tissues were tested for mercury. For the purpose of comparison, four striped bass in an unpolluted lake were also caught and tested. The fish tissue mercury levels in mg/kg are given below.

Sample1(frompollutedlake)0.5800.7110.5710.6660.598Sample2(fromunpollutedlake)0.3820.2760.5700.366
1. Construct the 95% confidence interval for the difference in the population means based on these data.
2. Test, at the 5% level of significance, whether the data provide sufficient evidence to conclude that fish in the polluted lake have elevated levels of mercury in their tissue.
2. A genetic engineering company claims that it has developed a genetically modified tomato plant that yields on average more tomatoes than other varieties. A farmer wants to test the claim on a small scale before committing to a full-scale planting. Ten genetically modified tomato plants are grown from seeds along with ten other tomato plants. At the season’s end, the resulting yields in pound are recorded as below.

Sample1(geneticallymodified)20232725252527232422Sample2(regular)21212218202018252320
1. Construct the 99% confidence interval for the difference in the population means based on these data.
2. Test, at the 1% level of significance, whether the data provide sufficient evidence to conclude that the mean yield of the genetically modified variety is greater than that for the standard variety.
3. The coaching staff of a professional football team believes that the rushing offense has become increasingly potent in recent years. To investigate this belief, 20 randomly selected games from one year’s schedule were compared to 11 randomly selected games from the schedule five years later. The sample information on rushing yards per game (rypg) is summarized below.

n x s
rypg previously 20 112 24
rypg recently 11 114 21
1. Construct the 95% confidence interval for the difference in the population means based on these data.
2. Test, at the 5% level of significance, whether the data on rushing yards per game provide sufficient evidence to conclude that the rushing offense has become more potent in recent years.
4. The coaching staff of professional football team believes that the rushing offense has become increasingly potent in recent years. To investigate this belief, 20 randomly selected games from one year’s schedule were compared to 11 randomly selected games from the schedule five years later. The sample information on passing yards per game (pypg) is summarized below.

n x s
pypg previously 20 203 38
pypg recently 11 232 33
1. Construct the 95% confidence interval for the difference in the population means based on these data.
2. Test, at the 5% level of significance, whether the data on passing yards per game provide sufficient evidence to conclude that the passing offense has become more potent in recent years.
5. A university administrator wishes to know if there is a difference in average starting salary for graduates with master’s degrees in engineering and those with master’s degrees in business. Fifteen recent graduates with master’s degree in engineering and 11 with master’s degrees in business are surveyed and the results are summarized below.

n x s
Engineering 15 68,535 1627
1. Construct the 90% confidence interval for the difference in the population means based on these data.
2. Test, at the 10% level of significance, whether the data provide sufficient evidence to conclude that the average starting salaries are different.
6. A gardener sets up a flower stand in a busy business district and sells bouquets of assorted fresh flowers on weekdays. To find a more profitable pricing, she sells bouquets for 15 dollars each for ten days, then for 10 dollars each for five days. Her average daily profit for the two different prices are given below.

n x s
$15 10 171 26$10 5 198 29
1. Construct the 90% confidence interval for the difference in the population means based on these data.
2. Test, at the 10% level of significance, whether the data provide sufficient evidence to conclude the gardener’s average daily profit will be higher if the bouquets are sold at \$10 each.

1. (16.16,21.84),
2. (4.28,11.72)
1.
1. (0.13,0.47),
2. (1.14,3.46)
2.
1. T = 2.787,  t0.025=2.131, reject H0,
2. T = 1.831,  ±t0.025=±2.023, do not reject H0
3.
1. T=1.349 t0.10=1.303, reject H0,
2. T = 1.411,  ±t0.05=±1.678, do not reject H0
4.
1. T = 2.411,  df=28 p -value>0.01, do not reject H0,
2. T = 1.473,  df=49 p -value<0.10, reject H0
5.
1. T = 2.827,  df=55 p -value<0.01, reject H0.
2. T = 1.699,  df=63 p -value <0.10, reject H0
6.
1. 0.2267±0.2182,
2. T = 3.635,  df=7 t0.05=1.895, reject H0 (elevated levels)
1.
1. 2±17.7,
2. T=0.232 df=29 t0.05=1.699, do not reject H0 (not more potent)
2.
1. 5305±1227,
2. T = 7.395,  df=24 ±t0.05=±1.711, reject H0 (different)

## 9.3 Comparison of Two Population Means: Paired Samples

In all exercises for this section assume that the population of differences is normal.

1. Use the following paired sample data for this exercise.

Population1Population23528322635273526362935273629
1. Compute d and sd.
2. Give a point estimate for μ1μ2=μd.
3. Construct the 95% confidence interval for μ1μ2=μd from these data.
4. Test, at the 10% level of significance, the hypothesis that μ1μ2>7 as an alternative to the null hypothesis that μ1μ2=7.
2. Use the following paired sample data for this exercise.

Population1Population210381127106967311088
Population1Population290701189513010910683
1. Compute d and sd.
2. Give a point estimate for μ1μ2=μd.
3. Construct the 90% confidence interval for μ1μ2=μd from these data.
4. Test, at the 1% level of significance, the hypothesis that μ1μ2<24 as an alternative to the null hypothesis that μ1μ2=24.
3. Use the following paired sample data for this exercise.

Population1Population24053274255683450
1. Compute d and sd.
2. Give a point estimate for μ1μ2=μd.
3. Construct the 99% confidence interval for μ1μ2=μd from these data.
4. Test, at the 10% level of significance, the hypothesis that μ1μ212 as an alternative to the null hypothesis that μ1μ2=12.
4. Use the following paired sample data for this exercise.

Population1Population2196212165182181199201210190205
1. Compute d and sd.
2. Give a point estimate for μ1μ2=μd.
3. Construct the 98% confidence interval for μ1μ2=μd from these data.
4. Test, at the 2% level of significance, the hypothesis that μ1μ220 as an alternative to the null hypothesis that μ1μ2=20.

### Applications

1. Each of five laboratory mice was released into a maze twice. The five pairs of times to escape were:

Mouse 1 2 3 4 5
First release 129 89 136 163 118
Second release 113 97 139 85 75
1. Compute d and sd.
2. Give a point estimate for μ1μ2=μd.
3. Construct the 90% confidence interval for μ1μ2=μd from these data.
4. Test, at the 10% level of significance, the hypothesis that it takes mice less time to run the maze on the second trial, on average.
2. Eight golfers were asked to submit their latest scores on their favorite golf courses. These golfers were each given a set of newly designed clubs. After playing with the new clubs for a few months, the golfers were again asked to submit their latest scores on the same golf courses. The results are summarized below.

Golfer 1 2 3 4 5 6 7 8
Own clubs 77 80 69 73 73 72 75 77
New clubs 72 81 68 73 75 70 73 75
1. Compute d and sd.
2. Give a point estimate for μ1μ2=μd.
3. Construct the 99% confidence interval for μ1μ2=μd from these data.
4. Test, at the 1% level of significance, the hypothesis that on average golf scores are lower with the new clubs.
3. A neighborhood home owners association suspects that the recent appraisal values of the houses in the neighborhood conducted by the county government for taxation purposes is too high. It hired a private company to appraise the values of ten houses in the neighborhood. The results, in thousands of dollars, are

House County Government Private Company
1 217 219
2 350 338
3 296 291
4 237 237
5 237 235
6 272 269
7 257 239
8 277 275
9 312 320
10 335 335
1. Give a point estimate for the difference between the mean private appraisal of all such homes and the government appraisal of all such homes.
2. Construct the 99% confidence interval based on these data for the difference.
3. Test, at the 1% level of significance, the hypothesis that appraised values by the county government of all such houses is greater than the appraised values by the private appraisal company.
4. In order to cut costs a wine producer is considering using duo or 1 + 1 corks in place of full natural wood corks, but is concerned that it could affect buyers’s perception of the quality of the wine. The wine producer shipped eight pairs of bottles of its best young wines to eight wine experts. Each pair includes one bottle with a natural wood cork and one with a duo cork. The experts are asked to rate the wines on a one to ten scale, higher numbers corresponding to higher quality. The results are:

Wine Expert Duo Cork Wood Cork
1 8.5 8.5
2 8.0 8.5
3 6.5 8.0
4 7.5 8.5
5 8.0 7.5
6 8.0 8.0
7 9.0 9.0
8 7.0 7.5
1. Give a point estimate for the difference between the mean ratings of the wine when bottled are sealed with different kinds of corks.
2. Construct the 90% confidence interval based on these data for the difference.
3. Test, at the 10% level of significance, the hypothesis that on the average duo corks decrease the rating of the wine.
5. Engineers at a tire manufacturing corporation wish to test a new tire material for increased durability. To test the tires under realistic road conditions, new front tires are mounted on each of 11 company cars, one tire made with a production material and the other with the experimental material. After a fixed period the 11 pairs were measured for wear. The amount of wear for each tire (in mm) is shown in the table:

Car Production Experimental
1 5.1 5.0
2 6.5 6.5
3 3.6 3.1
4 3.5 3.7
5 5.7 4.5
6 5.0 4.1
7 6.4 5.3
8 4.7 2.6
9 3.2 3.0
10 3.5 3.5
11 6.4 5.1
1. Give a point estimate for the difference in mean wear.
2. Construct the 99% confidence interval for the difference based on these data.
3. Test, at the 1% level of significance, the hypothesis that the mean wear with the experimental material is less than that for the production material.
6. A marriage counselor administered a test designed to measure overall contentment to 30 randomly selected married couples. The scores for each couple are given below. A higher number corresponds to greater contentment or happiness.

Couple Husband Wife
1 47 44
2 44 46
3 49 44
4 53 44
5 42 43
6 45 45
7 48 47
8 45 44
9 52 44
10 47 42
11 40 34
12 45 42
13 40 43
14 46 41
15 47 45
16 46 45
17 46 41
18 46 41
19 44 45
20 45 43
21 48 38
22 42 46
23 50 44
24 46 51
25 43 45
26 50 40
27 46 46
28 42 41
29 51 41
30 46 47
1. Test, at the 1% level of significance, the hypothesis that on average men and women are not equally happy in marriage.
2. Test, at the 1% level of significance, the hypothesis that on average men are happier than women in marriage.

### Large Data Set Exercises

1. Large Data Set 5 lists the scores for 25 randomly selected students on practice SAT reading tests before and after taking a two-week SAT preparation course. Denote the population of all students who have taken the course as Population 1 and the population of all students who have not taken the course as Population 2.

http://www.gone.2012books.lardbucket.org/sites/all/files/data5.xls

1. Compute the 25 differences in the order  after before, their mean d, and their sample standard deviation sd.
2. Give a point estimate for μd=μ1μ2, the difference in the mean score of all students who have taken the course and the mean score of all who have not.
3. Construct a 98% confidence interval for μd.
4. Test, at the 1% level of significance, the hypothesis that the mean SAT score increases by at least ten points by taking the two-week preparation course.
2. Large Data Set 12 lists the scores on one round for 75 randomly selected members at a golf course, first using their own original clubs, then two months later after using new clubs with an experimental design. Denote the population of all golfers using their own original clubs as Population 1 and the population of all golfers using the new style clubs as Population 2.

http://www.gone.2012books.lardbucket.org/sites/all/files/data12.xls

1. Compute the 75 differences in the order  original clubs new clubs, their mean d, and their sample standard deviation sd.
2. Give a point estimate for μd=μ1μ2, the difference in the mean score of all golfers using their original clubs and the mean score of all golfers using the new kind of clubs.
3. Construct a 90% confidence interval for μd.
4. Test, at the 1% level of significance, the hypothesis that the mean golf score decreases by at least one stroke by using the new kind of clubs.
3. Consider the previous problem again. Since the data set is so large, it is reasonable to use the standard normal distribution instead of Student’s t-distribution with 74 degrees of freedom.

1. Construct a 90% confidence interval for μd using the standard normal distribution, meaning that the formula is d±zα/2sdn.(The computations done in part (a) of the previous problem still apply and need not be redone.) How does the result obtained here compare to the result obtained in part (c) of the previous problem?
2. Test, at the 1% level of significance, the hypothesis that the mean golf score decreases by at least one stroke by using the new kind of clubs, using the standard normal distribution. (All the work done in part (d) of the previous problem applies, except the critical value is now zα instead of tα (or the p-value can be computed exactly instead of only approximated, if you used the p-value approach).) How does the result obtained here compare to the result obtained in part (c) of the previous problem?
3. Construct the 99% confidence intervals for μd using both the t- and z-distributions. How much difference is there in the results now?

1. d=7.4286sd=0.9759,
2. d=7.4286,
3. (6.53,8.33),
4. T = 1.162, df=6t0.10=1.44, do not reject H0
1.
1. d=14.25sd=1.5,
2. d=14.25,
3. (18.63,9.87),
4. T=3.000df=3±t0.05=±2.353, reject H0
2.
1. d=25.2sd=35.6609,
2. 25.2,
3. 25.2±34.0
4. T = 1.580, df=4t0.10=1.533, reject H0 (takes less time)
1.
1. 3.2,
2. 3.2±7.5
3. T = 1.392, df=9t0.10=2.821, do not reject H0 (government appraisals not higher)
2.
1. 0.65,
2. 0.65±0.69,
3. T = 3.014, df=10t0.01=2.764, reject H0 (experimental material wears less)
3.
1. d=16.68 and sd=10.77
2. d=16.68
3. (11.31,22.05)
4. H0:μ1μ2=10 vs. Ha:μ1μ2>10. Test Statistic: T = 3.1014. d.f.=24. Rejection Region: [2.492,). Decision: Reject H0.
1.
1. (1.6266,2.6401). Endpoints change in the third deciaml place.
2. H0:μ1μ2=1 vs. Ha:μ1μ2>1. Test Statistic: Z = 3.6791. Rejection Region: [2.33,). Decision: Reject H0. The decision is the same as in the previous problem.
3. Using the tdistribution, (1.3188,2.9478). Using the zdistribution, (1.3401,2.9266). There is a difference.

## 9.4: Comparison of Two Population Proportions

### Basic

1. Construct the confidence interval for p1p2 for the level of confidence and the data given. (The samples are sufficiently large.)

1. 90% confidence,

n1=1670pˆ1=0.42

n2=900pˆ2=0.38

2. 95% confidence,

n1=600pˆ1=0.84

n2=420pˆ2=0.67

2. Construct the confidence interval for p1p2 for the level of confidence and the data given. (The samples are sufficiently large.)

1. 98% confidence,

n1=750pˆ1=0.64

n2=800pˆ2=0.51

2. 99.5% confidence,

n1=250pˆ1=0.78

n2=250pˆ2=0.51

3. Construct the confidence interval for p1p2 for the level of confidence and the data given. (The samples are sufficiently large.)

1. 80% confidence,

n1=300pˆ1=0.255

n2=400pˆ2=0.193

2. 95% confidence,

n1=3500pˆ1=0.147

n2=3750pˆ2=0.131

4. Construct the confidence interval for p1p2 for the level of confidence and the data given. (The samples are sufficiently large.)

1. 99% confidence,

n1=2250pˆ1=0.915

n2=2525pˆ2=0.858

2. 95% confidence,

n1=120pˆ1=0.650

n2=200pˆ2=0.505

5. Perform the test of hypotheses indicated, using the data given. Use the critical value approach. Compute the p-value of the test as well. (The samples are sufficiently large.)

1. Test H0:p1p2=0 vs. Ha:p1p2>0 @ α=0.10,

n1=1200pˆ1=0.42

n2=1200pˆ2=0.40

2. Test H0:p1p2=0 vs. Ha:p1p20 @ α=0.05,

n1=550pˆ1=0.61

n2=600pˆ2=0.67

6. Perform the test of hypotheses indicated, using the data given. Use the critical value approach. Compute the p-value of the test as well. (The samples are sufficiently large.)

1. Test H0:p1p2=0.05 vs. Ha:p1p2>0.05 @ α=0.05,

n1=1100pˆ1=0.57

n2=1100pˆ2=0.48

2. Test H0:p1p2=0 vs. Ha:p1p20 @ α=0.05,

n1=800pˆ1=0.39

n2=900pˆ2=0.43

7. Perform the test of hypotheses indicated, using the data given. Use the critical value approach. Compute the p-value of the test as well. (The samples are sufficiently large.)

1. Test H0:p1p2=0.25 vs. Ha:p1p2<0.25 @ α=0.005,

n1=1400pˆ1=0.57

n2=1200pˆ2=0.37

2. Test H0:p1p2=0.16 vs. Ha:p1p20.16 @ α=0.02,

n1=750pˆ1=0.43

n2=600pˆ2=0.22

8. Perform the test of hypotheses indicated, using the data given. Use the critical value approach. Compute the p-value of the test as well. (The samples are sufficiently large.)

1. Test H0:p1p2=0.08 vs. Ha:p1p2>0.08 @ α=0.025,

n1=450pˆ1=0.67

n2=200pˆ2=0.52

2. Test H0:p1p2=0.02 vs. Ha:p1p20.02 @ α=0.001,

n1=2700pˆ1=0.837

n2=2900pˆ2=0.854

9. Perform the test of hypotheses indicated, using the data given. Use the p-value approach. (The samples are sufficiently large.)

1. Test H0:p1p2=0 vs. Ha:p1p2<0 @ α=0.005,

n1=1100pˆ1=0.22

n2=1300pˆ2=0.27

2. Test H0:p1p2=0 vs. Ha:p1p20 @ α=0.01,

n1=650pˆ1=0.35

n2=650pˆ2=0.41

10. Perform the test of hypotheses indicated, using the data given. Use the p-value approach. (The samples are sufficiently large.)

1. Test H0:p1p2=0.15 vs. Ha:p1p2>0.15 @ α=0.10,

n1=950pˆ1=0.41

n2=500pˆ2=0.23

2. Test H0:p1p2=0.10 vs. Ha:p1p20.10 @ α=0.10,

n1=220pˆ1=0.92

n2=160pˆ2=0.78

11. Perform the test of hypotheses indicated, using the data given. Use the p-value approach. (The samples are sufficiently large.)

1. Test H0:p1p2=0.22 vs. Ha:p1p2>0.22 @ α=0.05,

n1=90pˆ1=0.72

n2=75pˆ2=0.40

2. Test H0:p1p2=0.37 vs. Ha:p1p20.37 @ α=0.02,

n1=425pˆ1=0.772

n2=425pˆ2=0.331

12. Perform the test of hypotheses indicated, using the data given. Use the p-value approach. (The samples are sufficiently large.)

1. Test H0:p1p2=0.50 vs. Ha:p1p2<0.50 @ α=0.10,

n1=40pˆ1=0.65

n2=55pˆ2=0.24

2. Test H0:p1p2=0.30 vs. Ha:p1p20.30 @ α=0.10,

n1=7500pˆ1=0.664

n2=1000pˆ2=0.319

### Applications

In all the remaining exercsises the samples are sufficiently large (so this need not be checked).

1. Voters in a particular city who identify themselves with one or the other of two political parties were randomly selected and asked if they favor a proposal to allow citizens with proper license to carry a concealed handgun in city parks. The results are:

Party A Party B
Sample size, n 150 200
Number in favor, x 90 140
1. Give a point estimate for the difference in the proportion of all members of Party A and all members of Party B who favor the proposal.
2. Construct the 95% confidence interval for the difference, based on these data.
3. Test, at the 5% level of significance, the hypothesis that the proportion of all members of Party A who favor the proposal is less than the proportion of all members of Party B who do.
4. Compute the p-value of the test.
2. To investigate a possible relation between gender and handedness, a random sample of 320 adults was taken, with the following results:

Men Women
Sample size, n 168 152
Number of left-handed, x 24 9
1. Give a point estimate for the difference in the proportion of all men who are left-handed and the proportion of all women who are left-handed.
2. Construct the 95% confidence interval for the difference, based on these data.
3. Test, at the 5% level of significance, the hypothesis that the proportion of men who are left-handed is greater than the proportion of women who are.
4. Compute the p-value of the test.
3. A local school board member randomly sampled private and public high school teachers in his district to compare the proportions of National Board Certified (NBC) teachers in the faculty. The results were:

Private Schools Public Schools
Sample size, n 80 520
Proportion of NBC teachers, pˆ 0.175 0.150
1. Give a point estimate for the difference in the proportion of all teachers in area public schools and the proportion of all teachers in private schools who are National Board Certified.
2. Construct the 90% confidence interval for the difference, based on these data.
3. Test, at the 10% level of significance, the hypothesis that the proportion of all public school teachers who are National Board Certified is less than the proportion of private school teachers who are.
4. Compute the p-value of the test.
4. In professional basketball games, the fans of the home team always try to distract free throw shooters on the visiting team. To investigate whether this tactic is actually effective, the free throw statistics of a professional basketball player with a high free throw percentage were examined. During the entire last season, this player had 656 free throws, 420 in home games and 236 in away games. The results are summarized below.

Home Away
Sample size, n 420 236
Free throw percent, pˆ 81.5% 78.8%
1. Give a point estimate for the difference in the proportion of free throws made at home and away.
2. Construct the 90% confidence interval for the difference, based on these data.
3. Test, at the 10% level of significance, the hypothesis that there exists a home advantage in free throws.
4. Compute the p-value of the test.
5. Randomly selected middle-aged people in both China and the United States were asked if they believed that adults have an obligation to financially support their aged parents. The results are summarized below.

China USA
Sample size, n 1300 150
Number of yes, x 1170 110

Test, at the 1% level of significance, whether the data provide sufficient evidence to conclude that there exists a cultural difference in attitude regarding this question.

6. A manufacturer of walk-behind push mowers receives refurbished small engines from two new suppliers, A and B. It is not uncommon that some of the refurbished engines need to be lightly serviced before they can be fitted into mowers. The mower manufacturer recently received 100 engines from each supplier. In the shipment from A, 13 needed further service. In the shipment from B, 10 needed further service. Test, at the 10% level of significance, whether the data provide sufficient evidence to conclude that there exists a difference in the proportions of engines from the two suppliers needing service.

### Large Data Set Exercises

1. Large Data Sets 6A and 6B record results of a random survey of 200 voters in each of two regions, in which they were asked to express whether they prefer Candidate A for a U.S. Senate seat or prefer some other candidate. Let the population of all voters in region 1 be denoted Population 1 and the population of all voters in region 2 be denoted Population 2. Let p1 be the proportion of voters in Population 1 who prefer Candidate A, and p2 the proportion in Population 2 who do.

http://www.gone.2012books.lardbucket.org/sites/all/files/data6A.xls

http://www.gone.2012books.lardbucket.org/sites/all/files/data6B.xls

1. Find the relevant sample proportions pˆ1 and pˆ2.
2. Construct a point estimate for p1p2.
3. Construct a 95% confidence interval for p1p2.
4. Test, at the 5% level of significance, the hypothesis that the same proportion of voters in the two regions favor Candidate A, against the alternative that a larger proportion in Population 2 do.
2. Large Data Set 11 records the results of samples of real estate sales in a certain region in the year 2008 (lines 2 through 536) and in the year 2010 (lines 537 through 1106). Foreclosure sales are identified with a 1 in the second column. Let all real estate sales in the region in 2008 be Population 1 and all real estate sales in the region in 2010 be Population 2.

http://www.gone.2012books.lardbucket.org/sites/all/files/data11.xls

1. Use the sample data to construct point estimates pˆ1 and pˆ2 of the proportions p1 and p2 of all real estate sales in this region in 2008 and 2010 that were foreclosure sales. Construct a point estimate of p1p2.
2. Use the sample data to construct a 90% confidence for p1p2.
3. Test, at the 10% level of significance, the hypothesis that the proportion of real estate sales in the region in 2010 that were foreclosure sales was greater than the proportion of real estate sales in the region in 2008 that were foreclosure sales. (The default is that the proportions were the same.)

1. (0.0068,0.0732),
2. (0.1163,0.2237)
1.
1. (0.0210,0.1030),
2. (0.0001,0.0319)
2.
1. Z = 0.996, z0.10=1.282p-value=0.1587, do not reject H0,
2. Z=2.120±z0.025=±1.960p-value=0.0340, reject H0
3.
1. Z=2.602z0.005=2.576p-value=0.0047, reject H0,
2. Z = 2.020, ±z0.01=±2.326p-value=0.0434, do not reject H0
4.
1. Z=2.85p-value=0.0022, reject H0,
2. Z=2.23p-value=0.0258, do not reject H0
5.
1. Z = 1.36, p-value=0.0869, do not reject H0,
2. Z = 2.32, p-value=0.0204, do not reject H0
6.
1. −0.10,
2. 0.10±0.101,
3. Z=1.943z0.05=1.645, reject H0 (fewer in Party A favor),
4. p-value = 0.0262
1.
1. 0.025,
2. 0.025±0.0745,
3. Z = 0.552, z0.10=1.282, do not reject H0 (as many public school teachers are certified),
4. p-value = 0.2912
2.
3. Z = 4.498, ±z0.005=±2.576, reject H0 (different)

4.
1. pˆ1=0.355 and pˆ2=0.41
2. pˆ1pˆ2=0.055
3. (0.1501,0.0401)
4. H0:p1p2=0 vs. Ha:p1p2<0. Test Statistic: Z=1.1335. Rejection Region: (,1.645]. Decision: Fail to reject H0.

## 9.5 Sample Size Considerations

1. Estimate the common sample size n of equally sized independent samples needed to estimate  μ1μ2 as specified when the population standard deviations are as shown.

1. 90% confidence, to within 3 units,  σ1=10 and  σ2=7
2. 99% confidence, to within 4 units,  σ1=6.8 and  σ2=9.3
3. 95% confidence, to within 5 units,  σ1=22.6 and  σ2=31.8
2. Estimate the common sample size n of equally sized independent samples needed to estimate  μ1μ2 as specified when the population standard deviations are as shown.

1. 80% confidence, to within 2 units,  σ1=14 and  σ2=23
2. 90% confidence, to within 0.3 units,  σ1=1.3 and  σ2=0.8
3. 99% confidence, to within 11 units,  σ1=42 and  σ2=37
3. Estimate the number n of pairs that must be sampled in order to estimate  μd=μ1μ2 as specified when the standard deviation sdof the population of differences is as shown.

1. 80% confidence, to within 6 units,  σd=26.5
2. 95% confidence, to within 4 units,  σd=12
3. 90% confidence, to within 5.2 units,  σd=11.3
4. Estimate the number n of pairs that must be sampled in order to estimate  μd=μ1μ2 as specified when the standard deviation sdof the population of differences is as shown.

1. 90% confidence, to within 20 units,  σd=75.5
2. 95% confidence, to within 11 units,  σd=31.4
3. 99% confidence, to within 1.8 units,  σd=4
5. Estimate the minimum equal sample sizes  n1=n2 necessary in order to estimate  p1p2 as specified.

1. 80% confidence, to within 0.05 (five percentage points)

1. when no prior knowledge of p1 or p2 is available
2. when prior studies indicate that  p10.20 and  p20.65
2. 90% confidence, to within 0.02 (two percentage points)

1. when no prior knowledge of p1 or p2 is available
2. when prior studies indicate that  p10.75 and  p20.63
3. 95% confidence, to within 0.10 (ten percentage points)

1. when no prior knowledge of p1 or p2 is available
2. when prior studies indicate that  p10.11 and  p20.37
6. Estimate the minimum equal sample sizes  n1=n2 necessary in order to estimate  p1p2 as specified.

1. 80% confidence, to within 0.02 (two percentage points)

1. when no prior knowledge of p1 or p2 is available
2. when prior studies indicate that  p10.78 and  p20.65
2. 90% confidence, to within 0.05 (two percentage points)

1. when no prior knowledge of p1 or p2 is available
2. when prior studies indicate that  p10.12 and  p20.24
3. 95% confidence, to within 0.10 (ten percentage points)

1. when no prior knowledge of p1 or p2 is available
2. when prior studies indicate that  p10.14 and  p20.21

### Applications

1. An educational researcher wishes to estimate the difference in average scores of elementary school children on two versions of a 100-point standardized test, at 99% confidence and to within two points. Estimate the minimum equal sample sizes necessary if it is known that the standard deviation of scores on different versions of such tests is 4.9.

2. A university administrator wishes to estimate the difference in mean grade point averages among all men affiliated with fraternities and all unaffiliated men, with 95% confidence and to within 0.15. It is known from prior studies that the standard deviations of grade point averages in the two groups have common value 0.4. Estimate the minimum equal sample sizes necessary to meet these criteria.

3. An automotive tire manufacturer wishes to estimate the difference in mean wear of tires manufactured with an experimental material and ordinary production tire, with 90% confidence and to within 0.5 mm. To eliminate extraneous factors arising from different driving conditions the tires will be tested in pairs on the same vehicles. It is known from prior studies that the standard deviations of the differences of wear of tires constructed with the two kinds of materials is 1.75 mm. Estimate the minimum number of pairs in the sample necessary to meet these criteria.

4. To assess to the relative happiness of men and women in their marriages, a marriage counselor plans to administer a test measuring happiness in marriage to n randomly selected married couples, record the their test scores, find the differences, and then draw inferences on the possible difference. Let  μ1 and  μ2 be the true average levels of happiness in marriage for men and women respectively as measured by this test. Suppose it is desired to find a 90% confidence interval for estimating  μd=μ1μ2 to within two test points. Suppose further that, from prior studies, it is known that the standard deviation of the differences in test scores is  σd10. What is the minimum number of married couples that must be included in this study?

5. A journalist plans to interview an equal number of members of two political parties to compare the proportions in each party who favor a proposal to allow citizens with a proper license to carry a concealed handgun in public parks. Let p1 and p2 be the true proportions of members of the two parties who are in favor of the proposal. Suppose it is desired to find a 95% confidence interval for estimating  p1p2 to within 0.05. Estimate the minimum equal number of members of each party that must be sampled to meet these criteria.

6. A member of the state board of education wants to compare the proportions of National Board Certified (NBC) teachers in private high schools and in public high schools in the state. His study plan calls for an equal number of private school teachers and public school teachers to be included in the study. Let p1 and p2 be these proportions. Suppose it is desired to find a 99% confidence interval that estimates  p1p2 to within 0.05.

1. Supposing that both proportions are known, from a prior study, to be approximately 0.15, compute the minimum common sample size needed.
2. Compute the minimum common sample size needed on the supposition that nothing is known about the values of p1 and p2.

n1=n280

n1=n234

n1=n2769

1. n1=n2=45,
2. n1=n2=56.
3. n1=n2=234

1. n1=n2=33.
2. n1=n2=35.
3. n1=n2=13

1. n1=n2=329,
2. n1=n2=255.
1. n1=n2=3383,
2. n1=n2=2846.
1. n1=n2=193,
2. n1=n2=128