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- https://stats.libretexts.org/Sandboxes/JolieGreen/Finite_Mathematics_-_Spring_2023_-_OER/11%3A_Probability/11.02%3A_Mutually_Exclusive_Events_and_the_Addition_RuleGiven two events, E, F, then finding the probability of E \(\cup\) F, is the same as finding the probability that E will happen, or F will happen, or both will happen. Let E be the event that the numb...Given two events, E, F, then finding the probability of E \(\cup\) F, is the same as finding the probability that E will happen, or F will happen, or both will happen. Let E be the event that the number shown on the die is an even number, and let F be the event that the number shown is greater than four. If we count the number of elements n(E) in E, and add to it the number of elements n(F) in F, the points in both E and F are counted twice, once as elements of E and once as elements of F.
- https://stats.libretexts.org/Under_Construction/Purgatory/FCC_-_Finite_Mathematics_-_Spring_2023/11%3A_Probability/11.02%3A_Mutually_Exclusive_Events_and_the_Addition_RuleGiven two events, E, F, then finding the probability of E \(\cup\) F, is the same as finding the probability that E will happen, or F will happen, or both will happen. Let E be the event that the numb...Given two events, E, F, then finding the probability of E \(\cup\) F, is the same as finding the probability that E will happen, or F will happen, or both will happen. Let E be the event that the number shown on the die is an even number, and let F be the event that the number shown is greater than four. If we count the number of elements n(E) in E, and add to it the number of elements n(F) in F, the points in both E and F are counted twice, once as elements of E and once as elements of F.
- https://stats.libretexts.org/Under_Construction/Purgatory/Finite_Mathematics_-_Spring_2023/11%3A_Probability/11.02%3A_Mutually_Exclusive_Events_and_the_Addition_RuleGiven two events, E, F, then finding the probability of E \(\cup\) F, is the same as finding the probability that E will happen, or F will happen, or both will happen. Let E be the event that the numb...Given two events, E, F, then finding the probability of E \(\cup\) F, is the same as finding the probability that E will happen, or F will happen, or both will happen. Let E be the event that the number shown on the die is an even number, and let F be the event that the number shown is greater than four. If we count the number of elements n(E) in E, and add to it the number of elements n(F) in F, the points in both E and F are counted twice, once as elements of E and once as elements of F.
- https://stats.libretexts.org/Courses/Fresno_City_College/New_FCC_DS_21_Finite_Mathematics_-_Spring_2023/11%3A_Probability/11.02%3A_Mutually_Exclusive_Events_and_the_Addition_Rule
- https://stats.libretexts.org/Courses/Fullerton_College/Math_100%3A_Liberal_Arts_Math_(Ikeda)/04%3A__Sets/4.02%3A_Union_Intersection_and_ComplementCommonly sets interact. For example, you and a new roommate decide to have a house party, and you both invite your circle of friends. At this party, two sets are being combined, though it might turn...Commonly sets interact. For example, you and a new roommate decide to have a house party, and you both invite your circle of friends. At this party, two sets are being combined, though it might turn out that there are some friends that were in both sets.
