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- https://stats.libretexts.org/Courses/Saint_Mary's_College_Notre_Dame/BFE_1201_Statistical_Methods_for_Finance_(Kuter)/05%3A_Point_Estimates/5.S%3A_Point_Estimates_(Solutions-_Practice__Homework)0.0003 25.07 2,507.40 \(N(10, \frac{10}{8}))\) 0.7799 1.69 0.0072 391.54 405.51 Mean = 25, standard deviation = 2/7 Mean = 48, standard deviation = 5/6 Mean = 90, standard deviation = 3/4 Mean = 120, ...0.0003 25.07 2,507.40 \(N(10, \frac{10}{8}))\) 0.7799 1.69 0.0072 391.54 405.51 Mean = 25, standard deviation = 2/7 Mean = 48, standard deviation = 5/6 Mean = 90, standard deviation = 3/4 Mean = 120, standard deviation = 0.38 Mean = 17, standard deviation = 0.17 Expected value = 17, standard deviation = 0.05 Expected value = 38, standard deviation = 0.43 Expected value = 14, standard deviation = 0.65 0.23 0.060 0.063 0.056 1/10 0.042 0.999 0.901 0.301 0.832 0.483 0.500 0.502 0.519 0.0087
- https://stats.libretexts.org/Courses/Fresno_City_College/Introduction_to_Business_Statistics_-_OER_-_Spring_2023/07%3A_The_Central_Limit_Theorem/7.12%3A_Chapter_Solution_(Practice__Homework)0.0003 25.07 7. 2,507.40 13. \(N(10, \frac{10}{8}))\) 0.7799 17. 1.69 19. 0.0072 21. 391.54 23. 405.51 25. Mean = 25, standard deviation = 2/7 26. Mean = 48, standard deviation = 5/6 27. Mean = 90, st...0.0003 25.07 7. 2,507.40 13. \(N(10, \frac{10}{8}))\) 0.7799 17. 1.69 19. 0.0072 21. 391.54 23. 405.51 25. Mean = 25, standard deviation = 2/7 26. Mean = 48, standard deviation = 5/6 27. Mean = 90, standard deviation = 3/4 28. Mean = 120, standard deviation = 0.38 29. Mean = 17, standard deviation = 0.17 30. Expected value = 17, standard deviation = 0.05 31. Expected value = 38, standard deviation = 0.43 32. Expected value = 14, standard deviation = 0.65 33. 0.23 34. 0.060 35. 1/5 36. b 64 61.
- https://stats.libretexts.org/Courses/Fresno_City_College/Book%3A_Business_Statistics_Customized_(OpenStax)/07%3A_The_Central_Limit_Theorem/7.12%3A_Chapter_Solution_(Practice__Homework)the length of a song, in minutes, in the collection \(U(2, 3.5)\) the average length, in minutes, of the songs from a sample of five albums from the collection \(N(2.75, 0.066)\) 2.74 minutes 0.03 min...the length of a song, in minutes, in the collection \(U(2, 3.5)\) the average length, in minutes, of the songs from a sample of five albums from the collection \(N(2.75, 0.066)\) 2.74 minutes 0.03 minutes 55. The mean of a sampling distribution of the means is approximately the mean of the data distribution. The standard deviation of the sampling distribution of the means will decrease making it approximately the same as the standard deviation of X as the sample size increases.