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5.11: Chapter Solution (Practice + Homework)
https://stats.libretexts.org/Courses/Fresno_City_College/Introduction_to_Business_Statistics_-_OER_-_Spring_2023/05%3A_Continuous_Random_Variables/5.11%3A_Chapter_Solution_(Practice__Homework)
Figure $\PageIndex{38}$ Figure $\PageIndex{41}$
5.11: Chapter Solution (Practice + Homework)
https://stats.libretexts.org/Courses/Fresno_City_College/Book%3A_Business_Statistics_Customized_(OpenStax)/05%3A_Continuous_Random_Variables/5.11%3A_Chapter_Solution_(Practice__Homework)
82. $P(X>650)=\frac{700-650}{700-300}=\frac{50}{400}=\frac{1}{8}=0.125$ . $P(400 <650)> 84. \(X =$ the useful life of a particular car battery, measured in months. $X$ is continuous. The cdf is \...82. $P(X>650)=\frac{700-650}{700-300}=\frac{50}{400}=\frac{1}{8}=0.125$ . $P(400 <650)> 84. \(X =$ the useful life of a particular car battery, measured in months. $X$ is continuous. The cdf is $P(T<t)> \(P(T<2)=1-1-e^{-\frac{2}{7}} \approx 0.2485$ . $P(T>15)=1-P(T<15)=1-\left(1-e^{-\frac{15}{7}}\right) \approx e^{-\frac{15}{7}} \approx 0.1173$ . $P(T>15 | T>10)=P(T>5)=1-\left(1-e^{-\frac{5}{7}}\right)=e^{-\frac{5}{7}} \approx 0.4895$ .
1.1: Uniform + Exponential Solution (Practice + Homework)
https://stats.libretexts.org/Courses/Saint_Mary's_College_Notre_Dame/BFE_1201_Statistical_Methods_for_Finance_(Kuter)/04%3A_Random_Variables/4.S%3A_Random_Variables_(Solutions-_Practice__Homework)/1.01%3A_Uniform__Exponential_Solution_(Practice__Homework)
Figure $\PageIndex{38}$ Figure $\PageIndex{41}$

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