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8.5: Calculating the Sample Size n- Continuous and Binary Random Variables
https://stats.libretexts.org/Courses/Fresno_City_College/Introduction_to_Business_Statistics_-_OER_-_Spring_2023/08%3A_Confidence_Intervals/8.05%3A_Calculating_the_Sample_Size_n-_Continuous_and_Binary_Random_Variables
From the problem, we know that the acceptable error, $e$ , is 0.03 (3%=0.03) and $z_{\frac{\alpha}{2}} Z_{0.05}=1.645$ because the confidence level is 90%. The acceptable error, $e$ , is the diffe...From the problem, we know that the acceptable error, $e$ , is 0.03 (3%=0.03) and $z_{\frac{\alpha}{2}} Z_{0.05}=1.645$ because the confidence level is 90%. The acceptable error, $e$ , is the difference between the actual population proportion p, and the sample proportion we expect to get from the sample.
6.5: Calculating the Sample Size n- Continuous and Binary Random Variables
https://stats.libretexts.org/Courses/Saint_Mary's_College_Notre_Dame/BFE_1201_Statistical_Methods_for_Finance_(Kuter)/06%3A_Interval_Estimates/6.05%3A_Calculating_the_Sample_Size_n-_Continuous_and_Binary_Random_Variables
From the problem, we know that the acceptable error, $\varepsilon$ , is 0.03 (3%=0.03) and $z_{\alpha/2} = z_{0.05}=1.645$ because the confidence level is 90%. The acceptable error, $\varepsilon$ ...From the problem, we know that the acceptable error, $\varepsilon$ , is 0.03 (3%=0.03) and $z_{\alpha/2} = z_{0.05}=1.645$ because the confidence level is 90%. The acceptable error, $\varepsilon$ , is the difference between the actual population proportion $p$ , and the sample proportion we expect to get from the sample.
8.5: Calculating the Sample Size n- Continuous and Binary Random Variables
https://stats.libretexts.org/Courses/Fresno_City_College/Book%3A_Business_Statistics_Customized_(OpenStax)/08%3A_Confidence_Intervals/8.05%3A_Calculating_the_Sample_Size_n-_Continuous_and_Binary_Random_Variables
From the problem, we know that the acceptable error, $e$ , is 0.03 (3%=0.03) and $z_{\frac{\alpha}{2}} Z_{0.05}=1.645$ because the confidence level is 90%. The acceptable error, $e$ , is the diffe...From the problem, we know that the acceptable error, $e$ , is 0.03 (3%=0.03) and $z_{\frac{\alpha}{2}} Z_{0.05}=1.645$ because the confidence level is 90%. The acceptable error, $e$ , is the difference between the actual population proportion p, and the sample proportion we expect to get from the sample.

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