It would be better to play a game with a positive expected value (good luck trying to find one!), although keep in mind that even if the average winnings are positive it could be the case that most pe...It would be better to play a game with a positive expected value (good luck trying to find one!), although keep in mind that even if the average winnings are positive it could be the case that most people lose money and one very fortunate individual wins a great deal of money. The probability that the third roll is different than the previous 2 is \(\dfrac{4}{6}\), so the probability that the 3 dice are different is \(\dfrac{5}{6} \cdot \dfrac{4}{6}=\dfrac{20}{36}\).