Skip to main content
Statistics LibreTexts

8.6: One-Sample t-tests and CIs Exercises

  • Page ID
    18056
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

     Practice Calculating t-tests

    Exercise \(\PageIndex{1}\)

    You are curious about how people feel about craft beer, so you gather data from 55 people in the city on whether or not they like it. You code your data so that 0 is neutral, positive scores indicate liking craft beer, and negative scores indicate disliking craft beer. You find that the average opinion was \(\overline{X} = 1.10\) and the spread was \(s = 0.40\), and you test for a difference from 0 at the \(α\)=0.05.

    Answer

    Based on opinions from 55 people, we can conclude that the average opinion of craft beer (\(\overline{X}\)=1.10) is positive, \(t(54)\)=22.00, \(p < .05\).

    Practice with Confidence Intervals

    Exercise \(\PageIndex{1}\)

    What is the relationship between a chosen level of confidence for a confidence interval and how wide that interval is? For instance, if you move from a 95% CI to a \(90\%\) CI, what happens? Hint: look at the t-table to see how critical values change when you change levels of significance.

    Answer

    As the level of confidence gets higher, the interval gets wider. In order to speak with more confidence about having found the population mean, you need to cast a wider net. This happens because critical values for higher confidence levels are larger, which creates a wider margin of error.

     

    Exercise \(\PageIndex{1}\)

    You hear a lot of talk about increasing global temperature, so you decide to see for yourself if there has been an actual change in recent years. You know that the average land temperature from 1951-1980 was 8.79 degrees Celsius (this is your population mean, \( \mu \). You find annual average temperature data from 1981-2017 (N=37) of 9.44 degrees Celsius with a standard deviation of 0.35 degrees Celsisum.  You decide to construct a \(99\%\) confidence interval (because you want to be as sure as possible and look for differences in both directions, not just one) using the  information to test for a difference from the previous average.  You can just do the math and report a statistical sentence.  

    Answer

    CI = (9.28, 9.60); CI does not bracket \(μ\), reject null hypothesis

    Contributors and Attributions


    This page titled 8.6: One-Sample t-tests and CIs Exercises is shared under a CC BY-NC-SA license and was authored, remixed, and/or curated by Michelle Oja.