solution7
- Page ID
- 64211
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Increasing the sample size while holding the level of confidence fixed will decrease the margin of error for a confidence interval.
We examine the formula: \( E = \pm \frac{z \sigma}{\sqrt{n}} \) Now increasing the sample size n increases the denominator. When the denominator gets larger, the fraction gets smaller. Hence, the margin of error will decrease when the sample size increases. The statement is true.
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