6.10: Chapter Solution (Practice + Homework)
- Page ID
- 5829
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)
1.
ounces of water in a bottle
3.
2
5.
–4
7.
–2
9.
The mean becomes zero.
11.
\(z = 2\)
13.
\(z = 2.78\)
15.
\(x = 20\)
17.
\(x = 6.5\)
19.
\(x = 1\)
21.
\(x = 1.97\)
23.
\(z = –1.67\)
25.
\(z \approx –0.33\)
27.
0.67, right
29.
3.14, left
31.
about 68%
33.
about 4%
35.
between –5 and –1
37.
about 50%
39.
about 27%
41.
The lifetime of a Sunshine CD player measured in years.
43.
\(P(x < 1)\)
45.
Yes, because they are the same in a continuous distribution: \(P(x = 1) = 0\)
47.
\(1 – P(x < 3)\) or \(P(x > 3)\)
49.
\(1 – 0.543 = 0.457\)
51.
0.0013
53.
0.1186
55.