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1.2: Chi-square (Solutions- Practice + Homework)

  • Page ID
    6140
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    1.

    mean = 25 and standard deviation = 7.0711

    3.

    when the number of degrees of freedom is greater than 90

    5.

    \(df = 2\)

    6.

    a test of a single variance

    8.

    a left-tailed test

    10.

    \(H_0: \sigma^2 = 0.812\);

    \(H_a: \sigma^2 > 0.812\).

    12.

    a test of a single variance

    16.

    a goodness-of-fit test

    18.

    3

    20.

    2.04

    21.

    We decline to reject the null hypothesis. There is not enough evidence to suggest that the observed test scores are significantly different from the expected test scores.

    23.

    \(H_0\): the distribution of AIDS cases follows the ethnicities of the general population of Santa Clara County.

    25.

    right-tailed

    27.

    2016.136

    28.

    • 30.

      a test of independence

      a test of independence

      34.

      8

      36.

      6.6

      39.

      Smoking level per day African American Native Hawaiian Latino Japanese Americans White Totals
      1-10 9,886 2,745 12,831 8,378 7,650 41,490
      11-20 6,514 3,062 4,932 10,680 9,877 35,065
      21-30 1,671 1,419 1,406 4,715 6,062 15,273
      31+ 759 788 800 2,305 3,970 8,622
      Totals 18,830 8,014 19,969 26,078 27,559 10,0450
      Table \(\PageIndex{54}\)

      41.

      Smoking level per day African American Native Hawaiian Latino Japanese Americans White
      1-10 7777.57 3310.11 8248.02 10771.29 11383.01
      11-20 6573.16 2797.52 6970.76 9103.29 9620.27
      21-30 2863.02 1218.49 3036.20 3965.05 4190.23
      31+ 1616.25 687.87 1714.01 2238.37 2365.49
      Table \(\PageIndex{55}\)

      43.

      10,301.8

      44.

      right

      46.

      1. 48.

        test for homogeneity

        test for homogeneity

        52.

        All values in the table must be greater than or equal to five.

        54.

        3

        57.

        a goodness-of-fit test

        59.

        a test for independence

        61.

        Answers will vary. Sample answer: Tests of independence and tests for homogeneity both calculate the test statistic the same way \(\sum_{(i j)} \frac{(O-E)^{2}}{E}\). In addition, all values must be greater than or equal to five.

        63.

        true

        65.

        false

        67.

        225

        69.

        \(H_0: \sigma^2 \leq 150\)

        71.

        36

        72.

        Check student’s solution.

        74.

        The claim is that the variance is no more than 150 minutes.

        76.

        a Student's \(t\)- or normal distribution

        78.

        1. 80.
          1. 82.
            1. 84.
              1. 87.
                Marital status Percent Expected frequency
                Never married 31.3 125.2
                Married 56.1 224.4
                Widowed 2.5 10
                Divorced/Separated 10.1 40.4
                Table \(\PageIndex{56}\)
                1. 89.
                  1. 91.
                    1. 94.

                      true

                      false

                      98.

                      1. 100.
                        1. 102.
                          1. 104.
                            1. 106.
                              1. 108.

                                true

                                true

                                112.

                                1. 114.
                                  1. 116.
                                    1. 118.
                                      1. 120.
                                        1. 122.
                                          1. The test statistic is always positive and if the expected and observed values are not close together, the test statistic is large and the null hypothesis will be rejected.
                                          2. Testing to see if the data fits the distribution “too well” or is too perfect.

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